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f[i][j]=f[i-1][j-1]+
位置数N
N=7
case 1
sum=
i-1=3
AB..... 3
A.B.... 2
A..B... 1
A...B.. 1
A....B. 2
A.....B 3
ABC.... 2
AB.C... 1
7-3 4
3
4=1+1+2
4=1+3
4=4
f1[i][j]
f2[i][j]
f3[i][j]
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Added by: dhy0077
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